MHT CET · Physics · Waves and Sound
A wire of length ' \(L\) ' and linear density ' \(m\) ' is stretched between two rigid supports with tension ' \(T\) '. It is observed that wire resonates in the \(\mathrm{P}^{\mathrm{th}}\) harmonic at a frequency of 320 Hz and resonates again at next higher frequency of 400 Hz . The value of ' \(p\) ' is
- A 2
- B 4
- C 8
- D 10
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & 320=\frac{\mathrm{p}}{2 l} \sqrt{\frac{\mathrm{~F}}{\mu}} \text { and } 400=\frac{\mathrm{p}+1}{2 l} \sqrt{\frac{\mathrm{~F}}{\mu}} \\ & \frac{400}{320}=\frac{\mathrm{p}+1}{\mathrm{p}} \Rightarrow 400 \mathrm{p}=320 \mathrm{p}+320 \\ & \mathrm{p}=4\end{aligned}\)
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