MHT CET · Physics · Mechanical Properties of Fluids
A wind with speed \(50 \mathrm{~m} / \mathrm{s}\) blows parallel to the roof of a house. The area of the roof is \(300 \mathrm{~m}^2\). Assume that the pressure inside the house is atmospheric pressure. Density of air is \(1.2 \mathrm{~kg} / \mathrm{m}^3\). The magnitude of the force exerted by the wind on the roof will be
- A \(1.5 \times 10^5 \mathrm{~N}\)
- B \(3.0 \times 10^5 \mathrm{~N}\)
- C \(4.5 \times 10^5 \mathrm{~N}\)
- D \(9.0 \times 10^5 \mathrm{~N}\)
Answer & Solution
Correct Answer
(C) \(4.5 \times 10^5 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(F = \frac{1}{2}\rho v^2 A\) \(F = \frac{1}{2} \times 1.2 \mathrm{~kg/m}^3 \times (50 \mathrm{~m/s})^2 \times 300 \mathrm{~m}^2\)
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