MHT CET · Physics · Rotational Motion
A wheel of radius \(2 \mathrm{~cm}\) is at rest on the horizontal surface. A point \(\mathrm{P}\) on circumference of the wheel is in contact with the horizontal surface. When the wheel rolls without slipping on the surface, the displacement of point P after half rotation of wheel is
- A \(2\left(\pi^{2}+2\right)^{\frac{1}{2}} \mathrm{~cm}\)
- B \(\left(\pi^{2}+2\right)^{\frac{1}{2}} \mathrm{~cm}\)
- C \(\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}\)
- D \(2\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(2\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\(\Delta x = \pi R\) \(\Delta y = 2R\)
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