MHT CET · Physics · Work Power Energy

A weightless string can support a tension up to \(30 \mathrm{~N}\). A stone of mass \(0.5 \mathrm{~kg}\) is tied to its one end and is revolved in a circular path of radius \(2 \mathrm{~m}\) in a vertical plane. Then the maximum angular velocity of the stone will be (acceleration due to gravity \(g=10 \mathrm{~m} / \mathrm{s}^2\) )

A \(10 \mathrm{rad} / \mathrm{s}\)
B \(\sqrt{60} \mathrm{rad} / \mathrm{s}\)
C \(\sqrt{30} \mathrm{rad} / \mathrm{s}\)
D \(5 \mathrm{rad} / \mathrm{s}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(5 \mathrm{rad} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

Considering force balance:
\(\begin{aligned} & T_{\max }=m \omega_{\max }^2 r+m g \\ & \Rightarrow \frac{T_{\text {max }}}{m}=\omega_{\max }^2 r+g \\ & \Rightarrow \frac{30 \mathrm{~N}}{0.5 \mathrm{~kg}}-10 \mathrm{~m} / \mathrm{s}^2=\omega_{\max }^2 r \\ & \Rightarrow \omega_{\max }=\sqrt{\frac{50}{2}}=5 \mathrm{rad} / \mathrm{s}\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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