MHT CET · Physics · Laws of Motion
A weight \(W\) can be just supported on a rough inclined place by a force \(F\) either acting along the plane or horizontally. If \(\theta\) is the angle of friction, then \(\mathrm{F} / \mathrm{W}\) is
- A \(\tan \theta\)
- B \(\sec \theta\)
- C \(\sin \theta\)
- D \(\cos \theta\)
Answer & Solution
Correct Answer
(A) \(\tan \theta\)
Step-by-step Solution
Detailed explanation
Angle of friction, is the angle which the resultant of limiting friction and normal reaction makes with the normal reaction.
\(\therefore\) \(\tan \theta=\frac{F}{R}\)
Or
\(\frac{F}{W}=\tan \theta\)
\(\therefore\) \(\tan \theta=\frac{F}{R}\)
Or
\(\frac{F}{W}=\tan \theta\)
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