MHT CET · Physics · Mechanical Properties of Fluids
A water drop of radius ' \(r\) ' and volume ' \(\mathrm{V}\) ' is kept in between the two identical glass plates such that it forms a thin layer of area ' \(\mathrm{A}\) ' between the plates. A force ' \(\mathrm{F}\) ' is applied such that the two plates separate from each other. The surface tension ' \(\mathrm{T}\) ' of the liquid is
- A \(\frac{F V}{2 A^2}\)
- B \(\frac{\mathrm{A}^2}{\mathrm{FV}}\)
- C \(\frac{\mathrm{AV}}{\mathrm{F}^2}\)
- D \(\frac{\mathrm{FV}}{4 \mathrm{~A}^2}\)
Answer & Solution
Correct Answer
(A) \(\frac{F V}{2 A^2}\)
Step-by-step Solution
Detailed explanation
Consider complete wetting.

The Laplace pressure jump is given by:
\(\Delta P =\frac{ T }{( R )}=\frac{ F }{ A }\quad\ldots(1)\)
On considering volume conservation: \(\frac{4}{3} \pi r^3=V \approx A(2 R)\)
\(\therefore R \approx \frac{ V }{2 A}\quad\ldots(2)\)
On plugging into equation (1), \(\frac{\mathrm{T}}{\left(\frac{\mathrm{V}}{2 \mathrm{~A}}\right)}=\frac{\mathrm{F}}{\mathrm{A}}\)
\(\therefore \mathrm{T}=\frac{\mathrm{FV}}{2 \mathrm{~A}^2}\)

The Laplace pressure jump is given by:
\(\Delta P =\frac{ T }{( R )}=\frac{ F }{ A }\quad\ldots(1)\)
On considering volume conservation: \(\frac{4}{3} \pi r^3=V \approx A(2 R)\)
\(\therefore R \approx \frac{ V }{2 A}\quad\ldots(2)\)
On plugging into equation (1), \(\frac{\mathrm{T}}{\left(\frac{\mathrm{V}}{2 \mathrm{~A}}\right)}=\frac{\mathrm{F}}{\mathrm{A}}\)
\(\therefore \mathrm{T}=\frac{\mathrm{FV}}{2 \mathrm{~A}^2}\)
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