MHT CET · Physics · Oscillations
A vertical spring oscillates with period 6 second with mass \(m\) is suspended from it. When the mass is at rest, the spring is stretched through a distance of
(Take, acceleration due to gravity, \(\mathrm{g}=\pi^2=10 \mathrm{~m} / \mathrm{s}^2\) )
- A 10 m
- B 3 m
- C 6 m
- D 9 m
Answer & Solution
Correct Answer
(D) 9 m
Step-by-step Solution
Detailed explanation
\(T = 2\pi \sqrt{\frac{x}{g}}\) \(T^2 = 4\pi^2 \frac{x}{g}\)
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