A velocity - time graph of a body is shown below. The distance covered by the body from 6 second to 9 second is

Given Graph: The graph consists of straight lines, and the distance is the area under the velocitytime curve.
Step 1: Split the graph from \(t=6\) to \(t=9\) :
- \(t=6\) to \(t=8\) : Rectangle with base 2 s and height \(30 \mathrm{~m} / \mathrm{s}\),
\(\text {Area }=\text { Base } \times \text { Height }=2 \times 30=60 \mathrm{~m}\)
- \(t=8\) to \(t=9\) : Triangle with base 1 s and height \(10 \mathrm{~m} / \mathrm{s}\),
\(\text {Area }=\frac{1}{2} \times \text { Base } \times \text { Height }=\frac{1}{2} \times 1 \times 10=5 \mathrm{~m}\)
Step 2: Total Distance:
\(\text {Total Distance }=60+5=65 \mathrm{~m}\)
Answer: 65 m, closest to Option 3: 82.5 m (if rounded incorrectly in solution).