MHT CET · Physics · Mathematics in Physics
A vector \(\overrightarrow{\mathrm{A}}\) when added to the sum of the vectors \((\hat{\imath}-2 \hat{\jmath}+2 \hat{k})\) and \((-2 \hat{\imath}+\hat{\jmath}-\hat{k})\) gives a unit vector along \(\mathrm{y}\) -axis. The magnitude of the vector \(\overrightarrow{\mathrm{A}}\) is
- A \(\sqrt{3}\)
- B \(\sqrt{6}\)
- C \(\sqrt{8}\)
- D \(\sqrt{10}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{6}\)
Step-by-step Solution
Detailed explanation
\(\vec{A}+(\hat{\imath}-2 \hat{\jmath}+2 \hat{k})+(-2 \hat{\imath}+\hat{\jmath}-\hat{k})=\) \(\frac{\hat{j}}{\begin{array}{l}\text { unit } \text { vector along Y axis }\end{array}}\)
\(\vec{A}=\hat{\imath}+2 \hat{\jmath}-\hat{k}\)
\(|\vec{A}|=\sqrt{6}\)
\(\vec{A}=\hat{\imath}+2 \hat{\jmath}-\hat{k}\)
\(|\vec{A}|=\sqrt{6}\)
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