MHT CET · Physics · Mathematics in Physics
A vector \(\vec{A}\) having magnitude 6 units is added to vector \(\overrightarrow{\mathrm{B}}\), which is along \(\mathrm{x}\) -axis. The resultant of \(\vec{A}\) and \(\vec{B}\) is along \(Y\) axis. If the magnitude of the resultant of \(\vec{A}\) and \(\vec{B}\) is three times that of \(\vec{B}\) then magnitude of \(\vec{B}\) is
- A \(\sqrt{1 \cdot 8}\)
- B \(\sqrt{2 \cdot 4}\)
- C \(\sqrt{3 \cdot 6}\)
- D \(\sqrt{1 \cdot 2}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{3 \cdot 6}\)
Step-by-step Solution
Detailed explanation
\([R]=[L],[P]=[L],[Q]=[L]\)
Also, \(\left[\frac{P^{2}-Q^{2}}{2}\right]=\left[L^{2}\right]\)
\(\Rightarrow \pi R\left[\frac{P^{2}-Q^{2}}{2}\right]=\left[L^{3}\right]=[x]=[\) volume \(]\)
Also, \(\left[\frac{P^{2}-Q^{2}}{2}\right]=\left[L^{2}\right]\)
\(\Rightarrow \pi R\left[\frac{P^{2}-Q^{2}}{2}\right]=\left[L^{3}\right]=[x]=[\) volume \(]\)
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