MHT CET · Physics · Waves and Sound
A uniform metal wire of length 'L', mass ' M' and density ' 0 ' is under a tension ' \(\mathrm{T}^{\prime}\) '. If the speed of transverse wave along the wire is ' \(V^{\prime}\), then area of cross-section of the wire is
- A \(\frac{\mathrm{V}}{\mathrm{Te}}\)
- B \(\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}\)
- C \(\frac{\mathrm{T}^{2}}{\mathrm{~V}_{\mathrm{Q}}}\)
- D \(\frac{\mathrm{V}^{2}}{\mathrm{~T} \mathrm{e}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{T}}{\mathrm{V}^{2}} \mathrm{Q}\)
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