MHT CET · Physics · Waves and Sound
A transverse displacement of vibrating string is \(y=0.06 \sin \left(\frac{2 \pi}{3}\right) x \cos (120 \pi t)\).
If the mass per unit length of a string is \(4 \times 10^{-2} \mathrm{~kg} / \mathrm{m}\), then the tension in the string will be
- A 1296 N
- B 1000 N
- C 720 N
- D 500 N
Answer & Solution
Correct Answer
(A) 1296 N
Step-by-step Solution
Detailed explanation
\(\omega = 120 \pi\), \(k = \frac{2 \pi}{3}\) \(v = \frac{\omega}{k} = \frac{120 \pi}{2 \pi / 3} = 180 \mathrm{~m/s}\)
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