MHT CET · Physics · Alternating Current
A transformer has 20 turns in the primary and 100 turns in the secondary coil. An ac voltage of \(\mathrm{V}_{\text {in }}=600 \sin 314 \mathrm{t}\) is applied to primary terminal of transformer. Then maximum value of secondary output voltage obtained in volt is
- A 600
- B 300
- C 3000
- D 6000
Answer & Solution
Correct Answer
(C) 3000
Step-by-step Solution
Detailed explanation
We know,
\(
\frac{V_s}{V_p}=\frac{N_s}{N_p}
\)
\(\therefore\) The maximum value of secondary output voltage is:
\(
\begin{aligned}
V_s & =\frac{N_s}{N_p} \times V_p=\frac{100}{20} \times 600 \\
V_s & =3000 V
\end{aligned}
\)
\(
\frac{V_s}{V_p}=\frac{N_s}{N_p}
\)
\(\therefore\) The maximum value of secondary output voltage is:
\(
\begin{aligned}
V_s & =\frac{N_s}{N_p} \times V_p=\frac{100}{20} \times 600 \\
V_s & =3000 V
\end{aligned}
\)
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