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MHT CET · Physics · Rotational Motion

A thin wire of length ' \(L\) ' and uniform linear mass density ' \(\lambda\) ' is bent into a circular ring. The moment of inertia of ring about a tangential axis in its plane is

  1. A \(\frac{3 \lambda L^2}{8 \pi^2}\)
  2. B \(\frac{8 \pi^2}{3 \lambda L^3}\)
  3. C \(\frac{3 \lambda L^3}{8 \pi^2}\)
  4. D \(\frac{8 \pi^2}{3 \lambda L^2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{3 \lambda L^3}{8 \pi^2}\)

Step-by-step Solution

Detailed explanation

\( M = \lambda L \) \( R = \frac{L}{2 \pi} \)