MHT CET · Physics · Wave Optics
A thin transparent plate of thickness \(t\) and refractive index \(\mu\) is introduced in the path of one of the two interfering waves. The path difference between these waves is changed by half the wavelength of light \(\lambda\). The thickness of the plate is
- A \(\frac{\lambda}{4(\mu-1)}\)
- B \(\frac{3 \lambda}{4(\mu-1)}\)
- C \(\frac{\lambda}{(\mu-1)}\)
- D \(\frac{\lambda}{2(\mu-1)}\)
Answer & Solution
Correct Answer
(D) \(\frac{\lambda}{2(\mu-1)}\)
Step-by-step Solution
Detailed explanation
Path difference after passing through a plate of thickness \(t\) and refractive index \(\mu\) is given by,
\(\Delta x=(\mu-1) t=\frac{\lambda}{2}\)
\(\therefore t=\frac{\lambda}{2(\mu-1)}\)
\(\Delta x=(\mu-1) t=\frac{\lambda}{2}\)
\(\therefore t=\frac{\lambda}{2(\mu-1)}\)
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