MHT CET · Physics · Waves and Sound
A string of mass 0.2 Kg is under a tension of 2.5 N . The length of the string is 2 m . A transverse wave starts from one end of the string. The time taken by the wave to reach the other end is
- A \(\quad 0.2 \mathrm{~s}\)
- B 0.4 s
- C 0.6 s
- D 0.8 s
Answer & Solution
Correct Answer
(B) 0.4 s
Step-by-step Solution
Detailed explanation
\(\therefore \quad\) Mass per unit length:
\(\begin{aligned}
& \mathrm{m}=\frac{\mathrm{M}}{l} \\
& \mathrm{~m}=\frac{0.2}{2}=0.1 \mathrm{~kg} / \mathrm{m}
\end{aligned}\)
\(\therefore \quad\) Velocity of transverse wave:
\(\begin{aligned}
& v=\sqrt{\frac{T}{m}} \\
& v=\sqrt{\frac{2.5}{0.1}}=5 \mathrm{~m} / \mathrm{s}
\end{aligned}\)
Time taken by the wave to reach other end is:
\(\mathrm{t}=\frac{l}{\mathrm{v}}=\frac{2}{5}=0.4 \mathrm{~s}\)
\(\begin{aligned}
& \mathrm{m}=\frac{\mathrm{M}}{l} \\
& \mathrm{~m}=\frac{0.2}{2}=0.1 \mathrm{~kg} / \mathrm{m}
\end{aligned}\)
\(\therefore \quad\) Velocity of transverse wave:
\(\begin{aligned}
& v=\sqrt{\frac{T}{m}} \\
& v=\sqrt{\frac{2.5}{0.1}}=5 \mathrm{~m} / \mathrm{s}
\end{aligned}\)
Time taken by the wave to reach other end is:
\(\mathrm{t}=\frac{l}{\mathrm{v}}=\frac{2}{5}=0.4 \mathrm{~s}\)
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