MHT CET · Physics · Motion In Two Dimensions
A string of length ' \(L\) ' fixed at one end carries a body of mass ' \(m\) ' at the other end. The mass is revolved in a circle in the horizontal plane about a vertical axis passing through the fixed end of the string. The string makes angle ' \(\theta\) ' with the vertical. The angular frequency of the body is ' \(\omega\) '. The tension in the string is
- A \(\mathrm{mL}^2 \omega\)
- B \(\mathrm{mL} \omega^2\)
- C \(\frac{\omega^2}{\mathrm{~mL}}\)
- D \(\frac{m \omega^2}{L}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{mL} \omega^2\)
Step-by-step Solution
Detailed explanation
In case of conical pendulum, the tension in the string provides the necessary centripetal force.
\(\therefore \quad \mathrm{T}=\mathrm{mr} \omega^2=\mathrm{mL} \omega^2 \quad \ldots(\) Here, \(\mathrm{r}=\mathrm{L})\)
\(\therefore \quad \mathrm{T}=\mathrm{mr} \omega^2=\mathrm{mL} \omega^2 \quad \ldots(\) Here, \(\mathrm{r}=\mathrm{L})\)
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