MHT CET · Physics · Waves and Sound
A string is vibrating in its fifth overtone between two rigid supports \(2.4 \mathrm{~m}\) apart. The distance between successive node and antinode is
- A \(0.8 \mathrm{~m}\)
- B \(0.2 \mathrm{~m}\)
- C \(0.1 \mathrm{~m}\)
- D \(0.6 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0.2 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
The correct option is (B).
If the string is clamped between two supports separated by L.
For the fundamental overtone separation between successive nodes is \(\mathrm{L}\).
For the first overtone separation between successive nodes is \(\frac{L}{2}\).
For the second overtone the separation between successive nodes will be \(\frac{L}{3}\).
So, for nth overtone the separation between successive nodes will be \(\frac{\mathrm{L}}{(\mathrm{n}+1)}\).
Therefore, for the fifth over separation between successive nodes will be \(\frac{\mathrm{L}}{6}\).
In the separation between successive node and antinode is half of the separation between two successive nodes.
So, \(\frac{\mathrm{L}}{12}=\frac{2.4 \mathrm{~m}}{12}=0.2 \mathrm{~m}\)
If the string is clamped between two supports separated by L.
For the fundamental overtone separation between successive nodes is \(\mathrm{L}\).
For the first overtone separation between successive nodes is \(\frac{L}{2}\).
For the second overtone the separation between successive nodes will be \(\frac{L}{3}\).
So, for nth overtone the separation between successive nodes will be \(\frac{\mathrm{L}}{(\mathrm{n}+1)}\).
Therefore, for the fifth over separation between successive nodes will be \(\frac{\mathrm{L}}{6}\).
In the separation between successive node and antinode is half of the separation between two successive nodes.
So, \(\frac{\mathrm{L}}{12}=\frac{2.4 \mathrm{~m}}{12}=0.2 \mathrm{~m}\)
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