MHT CET · Physics · Waves and Sound
A stretched string is fixed at both ends. It is made to vibrate so that the total number of nodes formed in it is ' \(x\) '. The length of the string in terms of the wavelength of waves formed in it is ( \(\lambda=\) wavelength)
- A \(\frac{\mathrm{X} \lambda}{2}\)
- B \(\left(\mathrm{X}+\frac{1}{2}\right) \frac{\lambda}{2}\)
- C \((X+1) \frac{\lambda}{2}\)
- D \((\mathrm{X}-1) \frac{\lambda}{2}\)
Answer & Solution
Correct Answer
(C) \((X+1) \frac{\lambda}{2}\)
Step-by-step Solution
Detailed explanation
For a string with fixed ends, the length is determined by the number of nodes (x). The length in terms of wavelength is given by \((X+1) \frac{\lambda}{2}\).
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