MHT CET · Physics · Magnetic Effects of Current
A straight wire carrying current 'I' is bent into a semi-circular arc of radius \({ }^{\prime} \mathrm{r}^{\prime}\), as shown. The magnitude of magnetic field at point '0' due to semi-circular arc is \(\left(\mu_{0}=\right.\) Permeability of free space)
- A \(\frac{\mu_{0} \text { I }}{4 \mathrm{r}}\)
- B \(\frac{\mu_{0} \mathrm{I}}{2 \mathrm{r}}\)
- C \(\frac{\mu_{0} \mathrm{I}}{\mathrm{r}^{2}}\)
- D \(\frac{\mu_{0} \mathrm{I}}{\mathrm{r}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_{0} \text { I }}{4 \mathrm{r}}\)
Step-by-step Solution
Detailed explanation
\(B=\frac{\mu_{0} I}{4 r}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- Two identical bar magnets each of magnetic moment 'M', separated by some distance are kept perpendicular to each other. The magnetic induction at a point at the same distance 'd' from the centre of magnets, is \(\quad\left(\mu_{0}=\right.\) permeability of free space \()\)MHT CET 2020 Easy
- The magnetic field at the centre of a current carrying circular coil of area ' A ' is ' B '. The magnetic moment \((\mathrm{M})\) of the coil is ( \(\mu_0=\) permeability of free space)MHT CET 2025 Medium
- A coil having ' N ' turns and resistance ' R ' \(\Omega\) is connected to a galvanometer of resistance '6R' \(\Omega\). The magnetic flux linked with this coil changes from \(\phi_1\) weber to \(\phi_2\) weber in time ' \(t\) ' second. The induced current in the circuit isMHT CET 2025 Medium
- A current ' I ' is flowing in a conductor PQRST as shown in figure. The radius of curved path QRS is ' R ' and length of straight portion PQ and ST is very large. The magnetic field at the centre [O] of the curved part is (\(\mu_0=\) permeability of free space)
MHT CET 2025 Medium - The path difference between two waves \(\mathrm{Y}_1=\mathrm{a}_1 \sin \left(\omega \mathrm{t}-\frac{2 \pi \mathrm{x}}{\lambda}\right)\) and \(\mathrm{Y}_2=\mathrm{a}_2 \cos \left(\omega \mathrm{t}-\frac{2 \pi \mathrm{x}}{\lambda}+\phi\right)\) isMHT CET 2024 Medium
- The compressibility of water is \(6 \times 10^{-10} \mathrm{~m}^{2} / \mathrm{N}\). If one litre of water is subjected to a pressure of \(4 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}\), then the decrease in its volume in millilitre will beMHT CET 2020 Easy
More PYQs from MHT CET
- The initial average kinetic energy of the molecules was E , when a gas sample is at \(27^{\circ} \mathrm{C}\). When the gas is heated to \(327^{\circ} \mathrm{C}\), then the final average kinetic energy will beMHT CET 2025 Easy
- If the surface tension of a soap solution is \(3 \times 10^{-2} \mathrm{~N} / \mathrm{m}\), then the work done in
forming a soap film of \(20 \mathrm{~cm} \times 5 \mathrm{~cm}\) will beMHT CET 2020 Easy - The gaseous plant hormone is ____________ .MHT CET 2022 Easy
- For the stationary wave
\(
y=4 \sin \left(\frac{\pi x}{15}\right) \cos (96 \pi t)
\)
the distance between a node and the next antinode isMHT CET 2011 Easy - Identify Hinsberg reagent from following.MHT CET 2022 Easy
- Select the CORRECT match:
Column A Column B i. Seminal fluid a. Corpus spongiosum ii. Prostate gland b. Membranous urethra iii. Ejaculatory duct c. Clitoris iv. Erectile tissues d. Fructose e. Prostaglandins MHT CET 2017 Medium