MHT CET · Physics · Work Power Energy
A stone is projected with kinetic energy E, making an angle \(\theta\) with the horizontal. When it reaches a highest point, its kinetic energy is
- A \(E^2 \sin ^2 \theta\)
- B \(E \sin \theta\)
- C \(\mathrm{E} \cos ^2 \theta\)
- D \(E \cos \theta\)
Answer & Solution
Correct Answer
(C) \(\mathrm{E} \cos ^2 \theta\)
Step-by-step Solution
Detailed explanation
\(E = \frac{1}{2}mv^2\). At highest point, \(v_H = v \cos \theta\). \(E_H = \frac{1}{2}mv_H^2 = \frac{1}{2}m(v \cos \theta)^2 = (\frac{1}{2}mv^2)\cos^2 \theta = E \cos^2 \theta\).
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