MHT CET · Physics · Alternating Current
A step down transformer is used to reduce the main supply from ' \(V_1\) ' volt to ' \(V_2\) ' volt. The primary coil draws a current ' \(I_1\) ' A and the secondary coil draws ' \(I_2\) ' A. \(\left(I_1 < I_2\right)\). The ratio of input power to output power is
- A \(\frac{\mathrm{V}_1 \mathrm{~V}_2}{\mathrm{I}_1 \mathrm{I}_2}\)
- B \(\frac{\mathrm{I}_1 \mathrm{~V}_1}{\mathrm{I}_2 \mathrm{~V}_2}\)
- C \(\frac{\mathrm{I}_1 \mathrm{I}_2}{\mathrm{~V}_1 \mathrm{~V}_2}\)
- D \(\frac{\mathrm{V}_1 \mathrm{I}_2}{\mathrm{~V}_2 \mathrm{I}_1}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{I}_1 \mathrm{~V}_1}{\mathrm{I}_2 \mathrm{~V}_2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Input power }=\mathrm{I}_1 \mathrm{~V}_1 \\ & \text { Output power }=\mathrm{I}_2 \mathrm{~V}_2\end{aligned}\)
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