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MHT CET · Physics · Alternating Current

A step-down transformer has \(N_{\mathrm{S}}\) to \(N_{\mathrm{p}}\) ratio of \(20: 1\). If \(8 \mathrm{~V}\) are developed across \(0.4 \Omega\) secondary, the primary current will be

  1. A \(1 \mathrm{~A}\)
  2. B \(0.5 \mathrm{~A}\)
  3. C \(4 \mathrm{~A}\)
  4. D \(2 \mathrm{~A}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1 \mathrm{~A}\)

Step-by-step Solution

Detailed explanation

For a step-down transformer:
\(\frac{N_{\mathrm{P}}}{N_{\mathrm{S}}}=\frac{20}{1}=\frac{V_p}{V_{\mathrm{s}}}=\frac{I_s}{I_p}\)
\(\begin{aligned} & \therefore I_s=\frac{8 \mathrm{~V}}{0.4 \mathrm{~A}}=20 \mathrm{~A} \\ & \Rightarrow I_p=I_s \times \frac{1}{20}=1 \mathrm{~A}\end{aligned}\)
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