MHT CET · Physics · Electrostatics
A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance \(1.21 Å\) Å between them. The wavelength of the standing wave is
- A \(1.21 Å\)
- B \(1.42 Å\)
- C \(6.05 Å\)
- D \(3.63 Å\)
Answer & Solution
Correct Answer
(A) \(1.21 Å\)
Step-by-step Solution
Detailed explanation
Key Idea The given standing wave has 2 segments.
The given standing wave is shown in the figure.
As length of one loop or segment is \(\frac{\lambda}{2}\), so length of 2 segments is \(2\left(\frac{\lambda}{2}\right)\). \(\therefore \quad 2 \frac{\lambda}{2}=1.21 Å\)
\(\Rightarrow \quad \lambda=1.21 Å\)
The given standing wave is shown in the figure.
As length of one loop or segment is \(\frac{\lambda}{2}\), so length of 2 segments is \(2\left(\frac{\lambda}{2}\right)\). \(\therefore \quad 2 \frac{\lambda}{2}=1.21 Å\)
\(\Rightarrow \quad \lambda=1.21 Å\)
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