MHT CET · Physics · Mechanical Properties of Fluids
A square frame of each side ' \(L\) ' is dipped in a soap solution and taken out. The force acting on the film formed is \((\mathrm{T}=\) surface tension of soap solution)
- A 8TL
- B 2TL
- C 4TL
- D \(6 \mathrm{TL}\)
Answer & Solution
Correct Answer
(A) 8TL
Step-by-step Solution
Detailed explanation
Soap film has two surfaces.
Net force acting on frame \(=2\) (force on one surface)
\(\begin{aligned} & =2 \times \mathrm{T} \times \text { (perimeter) } \\ & =2 \times \mathrm{T} \times 4 \mathrm{~L}\end{aligned}\)
Net force acting on the square frame \(=8 \mathrm{TL}\)
Net force acting on frame \(=2\) (force on one surface)
\(\begin{aligned} & =2 \times \mathrm{T} \times \text { (perimeter) } \\ & =2 \times \mathrm{T} \times 4 \mathrm{~L}\end{aligned}\)
Net force acting on the square frame \(=8 \mathrm{TL}\)
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