MHT CET · Physics · Magnetic Effects of Current
A square coil ABCD of side ' L ' is carrying a current in clockwise direction. A straight conductor carrying current \(\mathrm{I}_2\) (upward direction) is kept parallel to side \(A B\) at a distance \(\frac{L}{3}\) in the plane of \(A B C D\). The net force on the coil ABCD is ( \(\mu_0=\) magnetic permeability)
- A \(\frac{\mu_0 \mathrm{I}_1 \mathrm{I}_2}{3 \pi}\)
- B \(\frac{3 \mu_0 \mathrm{I}_1 \mathrm{I}_2}{4 \pi}\)
- C \(\frac{3 \mu_0 \mathrm{I}_1 \mathrm{I}_2}{8 \pi}\)
- D \(\frac{9 \mu_0 I_1 I_2}{8 \pi}\)
Answer & Solution
Correct Answer
(D) \(\frac{9 \mu_0 I_1 I_2}{8 \pi}\)
Step-by-step Solution
Detailed explanation
\(F_{AB} = \frac{\mu_0 I_1 I_2 L}{2 \pi (L/3)} = \frac{3 \mu_0 I_1 I_2}{2 \pi}\) (attractive) \(F_{CD} = \frac{\mu_0 I_1 I_2 L}{2 \pi (4L/3)} = \frac{3 \mu_0 I_1 I_2}{8 \pi}\) (repulsive)
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