MHT CET · Physics · Oscillations
A spring executes S.H.M. with mass 1 kg attached to it. The force constant of the spring is \(4 \mathrm{~N} / \mathrm{m}\). If at any instant its velocity is \(20 \mathrm{~cm} / \mathrm{s}\), the displacement at that instant is
(Amplitude of S.H.M. is 0.4 m )
- A \(\sqrt{0.11} \mathrm{~m}\)
- B \(\sqrt{0.15} \mathrm{~m}\)
- C \(\sqrt{0.17} \mathrm{~m}\)
- D \(\sqrt{0.19} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{0.15} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(\omega = \sqrt{k/m} = \sqrt{4/1} = 2 \mathrm{~rad/s}\) \(x = \sqrt{A^2 - (v/\omega)^2}\)
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