MHT CET · Physics · Work Power Energy
A sphere is suspended by a thread of length \(l\) What minimum horizontal velocity has to be imparted the ball for it to reach the height of the suspension?
- A \(\mathrm{gl}\)
- B \(2 \mathrm{gl}\)
- C \(\sqrt{2 g l}\)
- D \(\sqrt{g l}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{g l}\)
Step-by-step Solution
Detailed explanation
KE given to a sphere at lowest point
= potential energy at the height of suspension \(\frac{1}{2} m v^{2}=m g l\)
\(\therefore\) \(v=\sqrt{2 g l}\)
= potential energy at the height of suspension \(\frac{1}{2} m v^{2}=m g l\)
\(\therefore\) \(v=\sqrt{2 g l}\)
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