MHT CET · Physics · Electrostatics
A sphere ' \(A\) ' of radius ' \(R\) ' has a charge ' \(Q\),' on it. The field at point \(B\) outside the sphere is ' \(E\) '. Now another sphere of radius ' \(2 R\) ' having a charge ' \(-2 Q\) ' is placed at \(B\). The total field at the point midway between A and B due to both the spheres is
- A E
- B 3 E
- C 12 E
- D 15 E
Answer & Solution
Correct Answer
(C) 12 E
Step-by-step Solution
Detailed explanation

The field at point ' \(B\) ' due to sphere of charge 'Q' will be,
\(\mathrm{E}=\frac{\mathrm{KQ}}{\mathrm{r}^2}\)
Electric field at mid-way between points ' \(A\) ' and ' \(B\) ' will be,
\(\begin{aligned}
E^{\prime} & =\frac{K Q}{\left(\frac{r}{2}\right)^2}+\frac{K(2 Q)}{\left(\frac{r}{2}\right)^2} \\
& =\frac{4 K Q}{r^2}+\frac{8 \mathrm{KQ}}{r^2} \\
E^{\prime} & =\frac{12 \mathrm{KQ}}{\mathrm{r}^2}=12 \mathrm{E}
\end{aligned}\)
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