MHT CET · Physics · Waves and Sound
A source and listener are both moving towards each other with speed \(\frac{\mathrm{V}}{10}\). (where V is speed of sound) If the frequency of sound note emitted by the source is ' \(n\) ', then the frequency heard by the listener would be nearly
- A 1.1 n
- B 1.22 n
- C n
- D 1.27 n
Answer & Solution
Correct Answer
(B) 1.22 n
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{n}^{\prime} & =\left(\frac{\mathrm{V}+\mathrm{V}_{\mathrm{L}}}{\mathrm{V}-\mathrm{V}_{\mathrm{S}}}\right) \mathrm{n} \\ & =\left(\frac{\mathrm{V}+\frac{\mathrm{V}}{10}}{\mathrm{~V}-\frac{\mathrm{V}}{10}}\right) \mathrm{n} \\ & =\frac{11}{9} \mathrm{n} \\ & =1.22 \mathrm{n}\end{aligned}\)
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