MHT CET · Physics · Waves and Sound
A sonometer wire resonates with 4 antinodes between two bridges for a given tuning fork, when \(1 \mathrm{~kg}\) mass is suspended from the wire. Using same fork, when mass \(M\) is suspended, the wire resonates producing 2 antinodes between the two bridges (distance between two bridges is as before). The value of \(M\) is
- A \(2.5 \mathrm{~kg}\)
- B \(3.5 \mathrm{~kg}\)
- C \(4 \mathrm{~kg}\)
- D \(1 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(C) \(4 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
If \(\mathrm{p}\) is the number of loops (or antinodes) then we have,
\(
\begin{aligned}
& \mathrm{f}=\frac{\mathrm{p}}{2 \ell} \sqrt{\frac{\mathrm{T}}{\mu}} \\
& \text { or } \quad \mathrm{Tp}^2=\text { constant } \\
& \therefore \mathrm{T}_1 \mathrm{p}_1^2=\mathrm{T}_2 \mathrm{p}_2^2 \\
& \text { or } \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\frac{\mathrm{p}_1^2}{\mathrm{p}_2^2}=\left(\frac{4}{2}\right)^2=4 \\
& \therefore \mathrm{T}_2=4 \mathrm{~T}_1=4 \mathrm{~kg}
\end{aligned}
\)
\(
\begin{aligned}
& \mathrm{f}=\frac{\mathrm{p}}{2 \ell} \sqrt{\frac{\mathrm{T}}{\mu}} \\
& \text { or } \quad \mathrm{Tp}^2=\text { constant } \\
& \therefore \mathrm{T}_1 \mathrm{p}_1^2=\mathrm{T}_2 \mathrm{p}_2^2 \\
& \text { or } \frac{\mathrm{T}_2}{\mathrm{~T}_1}=\frac{\mathrm{p}_1^2}{\mathrm{p}_2^2}=\left(\frac{4}{2}\right)^2=4 \\
& \therefore \mathrm{T}_2=4 \mathrm{~T}_1=4 \mathrm{~kg}
\end{aligned}
\)
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