ExamBro
ExamBro
MHT CET · Physics · Rotational Motion

A solid sphere rolling without friction on a horizontal surface with a constant speed of \(2 \mathrm{~m} / \mathrm{s}\), rolls up on an inclined ramp which is inclined at \(30^{\circ}\). The maximum distance travelled by the sphere on the inclined ramp is (acceleration due to gravity \(g=10 \mathrm{~m} / \mathrm{s}^2, \sin 30^{\circ}=1 / 2\))

  1. A 56 cm
  2. B 25 cm
  3. C 47 cm
  4. D 30 cm
Verified Solution

Answer & Solution

Correct Answer

(A) 56 cm

Step-by-step Solution

Detailed explanation

\(\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = mgh \implies \frac{1}{2}mv^2 + \frac{1}{2}\left(\frac{2}{5}mR^2\right)\left(\frac{v}{R}\right)^2 = mgh \implies \frac{7}{10}v^2 = gh \implies h = \frac{7v^2}{10g}\) \(d = \frac{h}{\sin\theta} = \frac{7v^2}{10g\sin\theta}\)