MHT CET · Physics · Rotational Motion
A solid sphere of radius ' \(R\) ' has mass ' \(M\) ' the moment of inertia of a solid sphere about an axis at a distance \(\left(\frac{\mathrm{R}}{2}\right)\) from the centre is
- A \(\frac{9}{20} \mathrm{MR}^2\)
- B \(\frac{7}{5} \mathrm{MR}^2\)
- C \(\frac{9}{5} \mathrm{MR}^2\)
- D \(\frac{13}{20} \mathrm{MR}^2\)
Answer & Solution
Correct Answer
(D) \(\frac{13}{20} \mathrm{MR}^2\)
Step-by-step Solution
Detailed explanation
Using parallel axis theorem:
\(I=\frac{2}{5} M R^2+M\left(\frac{R}{2}\right)^2=\frac{13}{20} M R^2\)
\(I=\frac{2}{5} M R^2+M\left(\frac{R}{2}\right)^2=\frac{13}{20} M R^2\)
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