MHT CET · Physics · Magnetic Effects of Current
A solenoid of 500 turns \(/ \mathrm{m}\) is carrying a current of 3 A. Its core is made of iron which has relative permeability 5001 . The magnitude of magnetization is
- A \(4.5 \times 10^6 \mathrm{Am}^{-1}\)
- B \(6.0 \times 10^{-6} \mathrm{Am}^{-1}\)
- C \(7.5 \times 10^6 \mathrm{Am}^{-1}\)
- D \(9.0 \times 10^6 \mathrm{Am}^{-1}\)
Answer & Solution
Correct Answer
(C) \(7.5 \times 10^6 \mathrm{Am}^{-1}\)
Step-by-step Solution
Detailed explanation
Given: \(\mathrm{n}=500\) turns \(/ \mathrm{m}, \mathrm{I}=3 \mathrm{~A}\)
\(\begin{aligned}
\mu_{\mathrm{r}}=5001 & \\
\therefore \quad \mu=\mathrm{nI} & =500 \times 3 \mathrm{~A} \\
& =1500 \mathrm{~A} / \mathrm{m} \\
\text { But, } \chi_{\mathrm{m}} & =\mu_{\mathrm{r}}-1 \\
& =5001-1 \\
& =5000
\end{aligned}\)
\(\begin{aligned}
\therefore \quad \text { Magnetization } \mathrm{M} & =\chi_{\mathrm{m}} \mathrm{H} \\
& =5000 \times 1500 \\
& =7.5 \times 10^6 \mathrm{Am}^{-1}
\end{aligned}\)
\(\begin{aligned}
\mu_{\mathrm{r}}=5001 & \\
\therefore \quad \mu=\mathrm{nI} & =500 \times 3 \mathrm{~A} \\
& =1500 \mathrm{~A} / \mathrm{m} \\
\text { But, } \chi_{\mathrm{m}} & =\mu_{\mathrm{r}}-1 \\
& =5001-1 \\
& =5000
\end{aligned}\)
\(\begin{aligned}
\therefore \quad \text { Magnetization } \mathrm{M} & =\chi_{\mathrm{m}} \mathrm{H} \\
& =5000 \times 1500 \\
& =7.5 \times 10^6 \mathrm{Am}^{-1}
\end{aligned}\)
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