MHT CET · Physics · Magnetic Properties of Matter
A solenoid having 400 turns per metre has a core of a material with relative permeability 400. When a current of 0.5 A is passed through it, the magnetization of the core material in \(\mathrm{Am}^{-1}\) is nearly
- A \(6 \times 10^5\)
- B \(6 \times 10^4\)
- C \(8 \times 10^5\)
- D \(8 \times 10^4\)
Answer & Solution
Correct Answer
(D) \(8 \times 10^4\)
Step-by-step Solution
Detailed explanation
Magnetic intensity,
\(\mathrm{H}=\mathrm{nI}=400 \times 0.5=200 \mathrm{Am}^{-1}\)
\(\mu_{\mathrm{r}}=1+\chi \Rightarrow \chi=\left(\mu_{\mathrm{r}}-1\right)\)
\(\begin{aligned} \therefore \quad \mathrm{M}=\chi \mathrm{H} & =\left(\mu_{\mathrm{r}}-1\right) \mathrm{H}=(400-1) \times 200 \\ & =7.98 \times 10^4 \mathrm{Am}^{-1} \\ & \approx 8 \times 10^4 \mathrm{Am}^{-1}\end{aligned}\)
\(\mathrm{H}=\mathrm{nI}=400 \times 0.5=200 \mathrm{Am}^{-1}\)
\(\mu_{\mathrm{r}}=1+\chi \Rightarrow \chi=\left(\mu_{\mathrm{r}}-1\right)\)
\(\begin{aligned} \therefore \quad \mathrm{M}=\chi \mathrm{H} & =\left(\mu_{\mathrm{r}}-1\right) \mathrm{H}=(400-1) \times 200 \\ & =7.98 \times 10^4 \mathrm{Am}^{-1} \\ & \approx 8 \times 10^4 \mathrm{Am}^{-1}\end{aligned}\)
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