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MHT CET · Physics · Oscillations

A simple pendulum starts oscillating simple harmonically from its mean position ( \(\mathrm{x}=0\) ) with amplitude ' a ' and periodic time ' T '. The magnitude of velocity of pendulum at \(X=\frac{a}{2}\) is

  1. A \(\frac{3 \pi^2 a}{T}\)
  2. B \(\frac{\sqrt{3} \pi a}{2 \mathrm{~T}}\)
  3. C \(\frac{\pi a}{\mathrm{~T}}\)
  4. D \(\frac{\sqrt{3} \pi a}{T}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\sqrt{3} \pi a}{T}\)

Step-by-step Solution

Detailed explanation

\(v = \omega \sqrt{a^2 - X^2}\) \(v = \frac{2\pi}{T} \sqrt{a^2 - \left(\frac{a}{2}\right)^2}\)
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