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MHT CET · Physics · Oscillations

A simple pendulum performs simple harmonic motion about \(\mathrm{x}=0\) with an amplitude ' \(\mathrm{a}\) ' and time period ' \(T\) '. The speed of the pendulum at \(x=\frac{a}{2}\) is

  1. A \(\frac{\pi \mathrm{a}}{\mathrm{T}}\)
  2. B \(\frac{3 \pi^2 \mathrm{a}}{\mathrm{T}}\)
  3. C \(\frac{\pi \mathrm{a} \sqrt{3}}{\mathrm{~T}}\)
  4. D \(\frac{\pi \mathrm{a} \sqrt{3}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\pi \mathrm{a} \sqrt{3}}{\mathrm{~T}}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} \mathrm{v} & =\omega \sqrt{\mathrm{a}^2-\mathrm{x}^2} \\ \text { At } \mathrm{x} & =\frac{\mathrm{a}}{2}, \\ \therefore \quad \mathrm{v} & =\omega \sqrt{\mathrm{a}^2-\frac{\mathrm{a}^2}{4}} \\ & =\omega \frac{\sqrt{3 \mathrm{a}}}{2} \\ & =\frac{2 \pi}{\mathrm{T}} \times \frac{\sqrt{3} \mathrm{a}}{2} \\ \therefore \quad \mathrm{v} & =\frac{\pi \mathrm{a} \sqrt{3}}{\mathrm{~T}}\end{aligned}\)