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MHT CET · Physics · Oscillations

A simple harmonic progressive wave is represented as \(Y=A \sin 2 \pi\left(n t-\frac{x}{\lambda}\right) \mathrm{cm}\). If the maximum particle velocity is four times the wave velocity, then the wavelength of the wave is

  1. A \(\frac{\pi \mathrm{A}}{4}\)
  2. B \(4 \pi \mathrm{A}\)
  3. C \(2 \pi \mathrm{A}\)
  4. D \(\frac{\pi \mathrm{A}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\pi \mathrm{A}}{2}\)

Step-by-step Solution

Detailed explanation

\(v_{p,max} = A\omega = A(2\pi n)\) \(v_{wave} = n\lambda\)