MHT CET · Physics · Communication System
A signal of frequency \(3 \mathrm{kHz}\) is amplitude modulated on a carrier wave of frequency \(2 \cdot 5 \mathrm{MHz}\). The upper and lower sideband frequencies in the resultant signal are
- A \(2500 \mathrm{kHz}, 2503 \mathrm{kHz}\)
- B \(2503 \mathrm{kHz}, 2497 \mathrm{kHz}\)
- C \(2 \cdot 5 \mathrm{MHz}, 3 \mathrm{kHz}\)
- D \(5 \cdot 5 \mathrm{MHz}, 0 \cdot 5 \mathrm{MHz}\)
Answer & Solution
Correct Answer
(B) \(2503 \mathrm{kHz}, 2497 \mathrm{kHz}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} f_{R}=f_{C}+f_{m} &=2500 \mathrm{KHz}+3 \mathrm{kz} \\ &=2503 \mathrm{KHz} \\ f_{R}=f_{C}-f_{m} &=2500 \mathrm{kHz}-3 \mathrm{kHz} \\ &=2497 \mathrm{kHz} \end{aligned}\)
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