MHT CET · Physics · Mechanical Properties of Solids
A rubber ball be taken in a deep sea so that its volume is decreased by \(x \%\). The
bulk modulus of rubber is 'K' and density of sea water is ' \(\varrho\) '. The depth to whÃch a rubber ball is taken is proportional to \((\mathrm{g}=\) acceleration due to gravity)
- A \(\frac{\text { ex }}{\mathrm{Kg}}\)
- B \(\frac{\mathrm{Kx}}{\mathrm{eg}}\)
- C \(\frac{\mathrm{eg}}{\mathrm{Kx}}\)
- D \(\frac{\mathrm{Q}}{\mathrm{Kxg}}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{Kx}}{\mathrm{eg}}\)
Step-by-step Solution
Detailed explanation
\(B=-\frac{\Delta p}{\Delta v / v}\)
\(\frac{\Delta v}{v}=\frac{x}{100}...(1)\)
\(\Delta p=\rho g h\)
\(\frac{\rho g h}{x / 100}\)
\(h \propto \frac{k x}{\rho g}\)
\(\frac{\Delta v}{v}=\frac{x}{100}...(1)\)
\(\Delta p=\rho g h\)
\(\frac{\rho g h}{x / 100}\)
\(h \propto \frac{k x}{\rho g}\)
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