MHT CET · Physics · Electrostatics
A regular hexagon of side 6 cm has a charge of \(2 \mu \mathrm{C}\) at each of its vertices, what is the potential at the centre of the hexagon?
\(\left[\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \text { SI unit }\right]\)
- A \(1.5 \times 10^5 \mathrm{~V}\)
- B \(1.8 \times 10^6 \mathrm{~V}\)
- C \(2.4 \times 10^5 \mathrm{~V}\)
- D \(3.2 \times 10^6 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(1.8 \times 10^6 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\(V = N k \frac{q}{r}\) \(V = 6 \times (9 \times 10^9) \times \frac{2 \times 10^{-6}}{0.06}\)
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