MHT CET · Physics · Thermal Properties of Matter
A rectangular black body of temperature \(127^{\circ} \mathrm{C}\) has surface area \(4 \mathrm{~cm} \times 2 \mathrm{~cm}\) and rate of radiation is E . If its temperature is increased by \(400^{\circ} \mathrm{C}\) and surface area is reduced to half of the initial value then the rate of radiation is
- A 8E
- B E
- C 2E
- D 16E
Answer & Solution
Correct Answer
(A) 8E
Step-by-step Solution
Detailed explanation
\(T_1 = 127 + 273 = 400 \mathrm{~K}\) \(A_1 = 4 \times 2 = 8 \mathrm{~cm}^2\)
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