ExamBro
ExamBro
MHT CET · Physics · Ray Optics

A ray of light travels from a denser medium to a rarer medium. The reflected and the refracted rays are perpendicular to each other. If ' \(\mathrm{r}\) ' and ' \(\mathrm{r}_1\) ' are the angle of reflection and refraction respectively and ' \(\mathrm{C}\) ' is the critical angle, then the angle of incidence is

  1. A \(\cot ^{-1}(\sin \mathrm{C})\)
  2. B \(\tan ^{-1}(\sin C)\)
  3. C \(\sin ^{-1}(\tan C)\)
  4. D \(\cos ^{-1}(\tan C)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\tan ^{-1}(\sin C)\)

Step-by-step Solution

Detailed explanation

Since reflected and refracted rays are perpendicular to each other,
\(
\begin{aligned}
& r+r_1=90^{\circ} \\
& \therefore r_1=90^{\circ}-r
\end{aligned}
\)
Refractive index of the denser medium
\(
\begin{aligned}
& \mu=\frac{\sin r_1}{\sin r}=\frac{\sin \left(90^{\circ}-r\right)}{\sin r}=\frac{\cos r}{\sin r}=\cot r \\
& \text { Also, } \mu=\frac{1}{\sin C} \quad \therefore \frac{1}{\sin C}=\cot r \\
& \text { or } \sin C=\tan r=\tan i \\
& \therefore i=\tan ^{-1}(\sin C)
\end{aligned}
\)
Same subject
Explore more questions on app