MHT CET · Physics · Ray Optics
A ray of light travelling through glass of refractive index \(\sqrt{2}\), is incident on glass - air boundary at an angle of incidence \(45^{\circ}\). If refractive index of air is 1 , then the angle of refraction will be \(\left[\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \quad \sin 90^{\circ}=1\right]\)
- A \(30^{\circ}\)
- B \(90^{\circ}\)
- C \(60^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(B) \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
(C)
\(\mu=\sqrt{2} \mathrm{i}=45^{\circ}\)
\(\mu_{i} \sin i=\mu_{r} \sin r\)
\(\Rightarrow \sqrt{2} \sin 45^{\circ}=\sin \mathrm{r}\)
\(\therefore \quad \mathrm{r}=90^{\circ}\)
\(\mu=\sqrt{2} \mathrm{i}=45^{\circ}\)
\(\mu_{i} \sin i=\mu_{r} \sin r\)
\(\Rightarrow \sqrt{2} \sin 45^{\circ}=\sin \mathrm{r}\)
\(\therefore \quad \mathrm{r}=90^{\circ}\)
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