MHT CET · Physics · Ray Optics
A ray of light passes through an equilateral prism such that the angle of incidence (i) is equal to angle of emergence (e). The angle of emergence is equal to \(\left(\frac{3}{4}\right)^{\text {th }}\) the angle of prism. The angle of deviation is
- A \(20^{\circ}\)
- B \(30^{\circ}\)
- C \(39^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(B) \(30^{\circ}\)
Step-by-step Solution
Detailed explanation
\(\therefore \quad \mathrm{i}=\mathrm{e}=60^{\circ} \times \frac{3}{4}=45^{\circ} \quad \ldots(\because\) prism is equilateral \()\)
Angle of Deviation: \(\delta=\mathrm{i}+\mathrm{e}-\mathrm{A}\) \(\delta=45^{\circ}+45^{\circ}-60^{\circ}=30^{\circ}\)
Angle of Deviation: \(\delta=\mathrm{i}+\mathrm{e}-\mathrm{A}\) \(\delta=45^{\circ}+45^{\circ}-60^{\circ}=30^{\circ}\)
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