MHT CET · Physics · Wave Optics
A ray of light is incident at polarising angle such that its deviation is \(24^{\circ}\), then angle of incidence is
- A \(24^{\circ}\)
- B \(57^{\circ}\)
- C \(66^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(B) \(57^{\circ}\)
Step-by-step Solution
Detailed explanation
Here, \(i_{p}=r+\delta\)

\(
i_{p}=r+24
\)
Moreover, \(i_{p}+r=90^{\circ}\)
...(ii) From Eqs. (i) and (ii), we get
\(i_{p}+\left(i_{p}-24\right) =90^{\circ}\)
\(\Rightarrow i_{p} =57^{\circ}\)

\(
i_{p}=r+24
\)
Moreover, \(i_{p}+r=90^{\circ}\)
...(ii) From Eqs. (i) and (ii), we get
\(i_{p}+\left(i_{p}-24\right) =90^{\circ}\)
\(\Rightarrow i_{p} =57^{\circ}\)
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