MHT CET · Physics · Wave Optics
A ray of light is incident at polarising angle ' \(\theta\) ' on air-glass interface, if ' \(\lambda_{\mathrm{a}}\) ' and ' \(\lambda_{\mathrm{g}}\) ' are the wavelengths of light in air and glass respectively, then
- A \(\lambda_g=\lambda_a \cot \theta\)
- B \(\lambda_a=\lambda_g \tan ^2 \theta\)
- C \(\lambda_g=\lambda_a \tan ^2 \theta\)
- D \(\lambda_a=\lambda_g \cot \theta\)
Answer & Solution
Correct Answer
(A) \(\lambda_g=\lambda_a \cot \theta\)
Step-by-step Solution
Detailed explanation
\( \mu = \tan \theta \) \( \mu = \frac{\lambda_{\mathrm{a}}}{\lambda_{\mathrm{g}}} \)
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