MHT CET · Physics · Ray Optics
A ray of light is incident at an angle of incidence 'i' on one surface of a thin prism of
small angle 'A'. The ray emerges normally from the opposite surface. If the refractive
index of the material of the prism is ' \(\mu\) ', the angle of incidence 'i' is nearly equal to
- A \(\underline{A}\)
- B \(\frac{\mu A}{2}\)
- C \(\mu A\)
- D \(\frac{A}{2 \mu}\)
Answer & Solution
Correct Answer
(C) \(\mu A\)
Step-by-step Solution
Detailed explanation
\(\mu=\frac{\sin \mathrm{i}}{\sin \mathrm{r}}=\frac{\mathrm{i}}{\mathrm{r}_{1}} \quad\) if angles are small.
\(A=r_{1}+r_{2}=r_{1}\)
since \(r_{2}=0\) since the ray emerges normally.
\(\therefore \mu=\frac{i}{A} \quad\) or \(\quad i=\mu A\)
\(A=r_{1}+r_{2}=r_{1}\)
since \(r_{2}=0\) since the ray emerges normally.
\(\therefore \mu=\frac{i}{A} \quad\) or \(\quad i=\mu A\)
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