MHT CET · Physics · Waves and Sound
A progressive wave of frequency \(50 \mathrm{~Hz}\) is travelling with velocity \(350 \mathrm{~m} / \mathrm{s}\) through a medium. The change in phase at a given time interval of \(0.01 \mathrm{~s}\) is
- A \(\pi \mathrm{rad}\)
- B \(\frac{\pi}{4} \mathrm{rad}\)
- C \(\frac{\pi}{2} \mathrm{rad}\)
- D \(\frac{3 \pi}{2} \mathrm{rad}\)
Answer & Solution
Correct Answer
(A) \(\pi \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
We know, \(\lambda \mathrm{f}=\mathrm{v}\)
\(\therefore \lambda=\frac{350}{50}=7 \mathrm{~m}\)
Path difference \(\mathrm{x}=\) Velocity \(\times\) time \(=350 \times 0.01=3.5 \mathrm{~m}\)
Phase change \(\frac{2 \pi x}{\lambda}=\frac{2 \pi}{7} \times 3.5=\pi\) radian
\(\therefore \lambda=\frac{350}{50}=7 \mathrm{~m}\)
Path difference \(\mathrm{x}=\) Velocity \(\times\) time \(=350 \times 0.01=3.5 \mathrm{~m}\)
Phase change \(\frac{2 \pi x}{\lambda}=\frac{2 \pi}{7} \times 3.5=\pi\) radian
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