MHT CET · Physics · Waves and Sound
A progressive wave of frequency \(50 \mathrm{~Hz}\) is travelling with velocity \(350 \mathrm{~m} / \mathrm{s}\) through a medium. The change in phase at a given time interval of 0.01 second is
- A \(\frac{\pi}{4} \mathrm{rad}\)
- B \(\frac{3 \pi}{2} \mathrm{rad}\)
- C \(\pi \mathrm{rad}\)
- D \(\frac{\pi}{2} \mathrm{rad}\)
Answer & Solution
Correct Answer
(C) \(\pi \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
& \frac{\text { Phase Difference }}{2 \pi}=\frac{\text { Time Difference }}{\mathrm{T}} \\
& \Rightarrow \Delta \phi=\frac{2 \pi}{\mathrm{T}} \times \Delta \mathrm{t}=\frac{2 \pi}{1 / 50} \times 0.01=\pi \text { radian }
\end{aligned}
\)
\begin{aligned}
& \frac{\text { Phase Difference }}{2 \pi}=\frac{\text { Time Difference }}{\mathrm{T}} \\
& \Rightarrow \Delta \phi=\frac{2 \pi}{\mathrm{T}} \times \Delta \mathrm{t}=\frac{2 \pi}{1 / 50} \times 0.01=\pi \text { radian }
\end{aligned}
\)
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